Sum of ages of father and son is 45
Web16 Nov 2024 · The sum of the ages of a father and his son is 45 years. Let the age of the son be S years, then the age of father will be ( 45 - S ) years. Five years ago, Age of the son will be ( S - 5 ) years. Age of the father will be ( 45 - S - 5 ) years = ( 40 - S ) years. According to the question, Five years ago, the product of their ages (in years ... Web45–15=30 The father was thirty when the son was born. In 15 years, the son will be 30 and the father will be 60. Aryan Singla Studied Science 2 y Since the sum of ages of son and father at present is 45. let the father’s age be x. Then the age of son is (45-x). 6 years ago, the sum of ages would be:- = (x-6)+ (45-x-6) =x-6+45-x-6 =45–12 =33
Sum of ages of father and son is 45
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WebThe sum of ages of a father and son is 45 years. Five years ago the product of their ages was 4 times the age of the father at that time. The present age of the father is A 30 yrs B 31 yrs C 36 yrs D 41 yrs Hard Solution Verified by Toppr Correct option is C) Let the present age of the father be x ∴ The present age of the son is (45−x) WebThe sum of the ages of a father and son is 45 years. Five years ago, the product of their ages was 34. Let age of father be ‘a’ and age of son is ‘b’ five years ago. According to question a x b = 34. There are only two possibilities to get a number 34 by multiplication of two numbers.
WebThis is nothing but a linear system whose unknowns are the ages of the two people. Just use variable. f = fathers age now. s = sons age now. f + 6 = fathers age in six years. s + 6 = sons age in six years. f = 5s. f+6 = 3 (s + 6). Two linear equations with two unknowns. Should be straightforward to solve. WebCarl Linnaeus (/ l ɪ ˈ n iː ə s, l ɪ ˈ n eɪ ə s /; 23 May 1707 – 10 January 1778), also known after his ennoblement in 1761 as Carl von Linné (Swedish pronunciation: [ˈkɑːɭ fɔn lɪˈneː] ()), was a Swedish botanist, zoologist, taxonomist, and physician who formalised binomial nomenclature, the modern system of naming organisms.He is known as the "father of …
WebThe sum of the ages of a father and son is 45 years. Five years ago, the produc... #PROBLEM ON AGES #PROBLEM ON AGES basic #PROBLEM ON AGES ShortTricks Q 34. Web4 Aug 2016 · So now we have their current sum 45 and product 144. We can list all factorizations of 234, of which there aren't many and find 234=39×6 works since 39+6=45. So the father is 39 years old and the son is 6 years old.
WebThe Sum of the Ages of a Father and His Son is 45 Years. Five Years Ago, the Product of Their Ages (In Year) Was 124. Determine Their Presnet Ages. CISCE ICSE Class 10 ... Father's age = 9 years, Son's age = (45 - x) = 36 years This is not possible Hence, x = 36 Father's age = 36 years
Web25 Oct 2024 · Best answer The correct answer is (b) Let age of Father=x Years Let age of son = y years x+y = 65 2 (x-y)=50 Solving the above equations Father’s Age =x = 45 years introverts are awesomeWeb27 May 2024 · Let the present age of father is And the present age of son is Six years ago, their ages were in the ratio 10 : 1 ∴ x − 6 45 − x − 6 = 10 1 x - 6 = 390 - 10x 11x = 396 x = 36 Therefore, present age of son is 9 The age of son after 6 years is 9 + 6 = 15 Hence, 15 is the correct answer. Download Solution PDF Latest SSC CPO Updates new pin systemWebx = 45 & y = 20. Suggest Corrections. 4. Similar questions. Q. The age of a man is 24 years more than the age of his son. If the sum of their ages is 50 years, find the age of the son and his father ... Sum of age of father and son is 55 years . If father was who lived in his son is equal to his present age , the total of their age woulbd be 93 ... introverts anonymousWebSum of ages of a father and his son = 45 years....(i) Five years ago, product of their ages = 124 years....(ii) Let, Present age of father = x years. Present age of son = (45−x) years(By using (i)) Now, forming a quadratic equation, ⇒(x−5)(45−x−5)=124(By using (ii)) ⇒(x−5)(40−x)=124. ⇒40x−x 2−200+5x=124. new pin port kemblaWeb13 Jan 2024 · The sum of ages of Father and his son is 45 years. 5 years ago, the product of their ages was 124. Determine present ages. - 49522499 introverts and multitaskingWebThe sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages (in years) was 124. Determine their present ages. Solution Let the present age of father = x years and the present age of son = y years According to question: x + y = 45 ... (1) Again, 5 years ago, the product of their ages was 124, therefore, introverts and eye contactWebTuguegarao 173 views, 16 likes, 22 loves, 45 comments, 0 shares, Facebook Watch Videos from Saint Rose of Lima Parish: Eucharistic Celebration, Monday... new pioneer avr 2023